// int a[]={1,3,5,7,9},*p=a;，则值为5的表达式是
// A、p+=2, *p++ B、p+=2, *++p C、p+=2, (*p)++ D、a+=2,*a
#include<stdio.h>
int main()
{
    int a[]={1,3,5,7,9},*p=a , x;
    if(!x)
    {
        printf("%d\n",p[2]); //5
    }
    printf("%d\n",*p++); //1
    printf("%d\n",*++p); //5 *++p先加1再取值
    printf("%d\n",(*p)++); //5
    printf("%d\n",*a); //1
    printf("%d\n",a[2]); //6
    printf("%d\n",*(a+2)); //6
    printf("%d\n",*(p+2)); //9
    return 0;
}